16x^2+64x=-48

Solution for 16x^2+64x=-48 equation:

16x^2+64x=-48

We move all terms to the left:

16x^2+64x-(-48)=0

We add all the numbers together, and all the variables

16x^2+64x+48=0

a = 16; b = 64; c = +48;
Δ = b2-4ac
Δ = 642-4·16·48
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-32}{2*16}=\frac{-96}{32}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+32}{2*16}=\frac{-32}{32}
=-1
$